-Object will be passed as copy of reference
-While passing primitive type as a method parameter, java passes copy of the primitive type to the calling method, so that the original value will be kept different from the copy, which results into two separate variables with separate memory locations.
Examples: int, long, double as a method parameters
-While passing reference type as a method parameter, java passes copy of reference to the calling method (copy of reference but not copy of Object). So original reference variable and its copy are pointing to the same Object memory location. which results into two reference variables pointing to the same Object memory location. With this you can modify Object states using either of the references (original or copy).
Fig. 1: Memory map for primitive and reference data types
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Example: To demonstrate how java passes parameters for primitive and reference data types.public class TestParamPass {
public static void main(String[] args) {
int age = 20; //primitive data type
Employee emp = new Employee(); //reference data type
System.out.println("Original age: " + age);
System.out.println("Original salary: " + emp.getSalary());
processAge(age, emp);
System.out.println("Updated age: " + age);
System.out.println("Updated Salary: " + emp.getSalary());
}
//Method to process passed parameters
private static void processAge(int ageParam, Employee empParam) {
empParam.setSalary(2000);
ageParam++;
}}
Output:
Original age: 20
Original salary: 0.0
Updated age: 20
Updated Salary: 2000.0
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double salary;
public double getSalary() {
return salary;
}
public void setSalary(double salary) {
this.salary = salary;
}
}
